1) By adding a resistor to circuit B this will cause a change in resistance, in this case the resistance within circuit B will be higher than circuit A. The change in resistance therefore causes the flow of charge (as resistors resist the flow of electrons) to change also. In this case the bulb in circuit B will be dimmer than circuit A.
2) Circuit B shows the correct way to use an ammeter, to measure the current within the circuit it must be connected in series; within circuit A the ammeter is connected in parallel which is incorrect.
3) In this circuit the reading on the ammeter is 1.12 amps
1.12amps= 1.12 coulombs per second
For one minute, 1.12*60= 67.2 coulombs
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